The word "algebra" means a number of different things.
It's the name of a whole field in mathematics, which covers objects like groups, rings, fields, and so forth. The sort of things defined, very handwavily, in terms of operations you can do with their elements and the equations they satisfy.
It's the name of a rather specific kind of mathematical structure: roughly, a vector space together with a way of multiplying its elements. (Motivating example: n-by-n matrices.)
It's the name (but usually with some qualifiers to make it clearer what you mean) for a broad range of mathematical structures, of which the one in the previous paragraph is a special case. See e.g. https://en.wikipedia.org/wiki/F-algebra.
Groups are among the things studied in the field of algebra. Groups aren't algebras in the second, specific, sense. They are F-algebras. Most mathematicians, most of the time, would not call groups "algebras" without some qualifier like that F- prefix.
The term "Clifford algebra" also means some different things.
A Clifford algebra is a particular sort of algebra-in-the-second-sense. The field called Clifford algebra is the study of those things. These days people more often say "geometric algebra" rather than "Clifford algebra" for that meaning.
There are mathematical objects called Clifford groups. They are not at all the same thing as Clifford algebras, and you can study Clifford algebras in some depth without paying any attention to the Clifford groups. But they are closely related to the Clifford algebras.
Both Clifford groups and Clifford algebras have applications in quantum physics and, more specifically, in quantum computing. But so far as I know the ways in which you use them in quantum computing has very little to do with the ways in which you use Clifford algebras for doing geometry. It is quite common in mathematics for the same (or equivalent) objects and structures to turn up in multiple places, in unrelated-looking ways. Sometimes this gives rise to deep connections between different fields; sometimes it's just a coincidence. I don't know enough about either quantum computation or geometric algebra to know which of those is going on here, but my intuition leans toward "coincidence".
So. vtomole's original comment was kinda-right and kinda-wrong: yes, there is a connection between Clifford algebras and quantum computation, but it doesn't have much to do with the stuff discussed, e.g., at the far end of the top-level link here. knzhou's question was a good one, pointing out that the two topics are quite separate. vtomole's reply "A group is an algebraic structure ..." didn't make any untrue statements but did miss the point; the fact that a group is an algebraic structure doesn't mean that something called "the X group" necessarily has anything to do with something called "the X algebra" -- though it happens that in this case there is a connection. (vtomole clearly got the point soon after, as seen from their subsequent replies.) knzhou was correct to point out that vtomole's reply missed the point. lisper, again, didn't say anything untrue but I think he missed the point. klodolph's comment about algebras versus universal algebras versus algebra was spot-on and the only reason why I went into more detail above is that it was apparently too brief to be clearly understood. monoideism is right that (e.g.) a group is a universal algebra, wrong to say that klodolph is self-contradictory, and I think missing the point that "algebra" is used with different meanings on different occasions, and in the phrase "Clifford algebra" the specific meaning in question is not "universal algebra". (Even though a Clifford algebra is, also, an example of a universal algebra.)
The fact that a group is a universal algebra doesn't at all licence any sort of blurring of the distinction between Clifford groups and Clifford algebras. The meaning of "algebra" in "Clifford algebra" is not "universal algebra" or "F-algebra", it is "vector space with multiplication", and a group simply isn't one of those (well, some groups are, but e.g. the Clifford groups are not).
It's the name of a whole field in mathematics, which covers objects like groups, rings, fields, and so forth. The sort of things defined, very handwavily, in terms of operations you can do with their elements and the equations they satisfy.
It's the name of a rather specific kind of mathematical structure: roughly, a vector space together with a way of multiplying its elements. (Motivating example: n-by-n matrices.)
It's the name (but usually with some qualifiers to make it clearer what you mean) for a broad range of mathematical structures, of which the one in the previous paragraph is a special case. See e.g. https://en.wikipedia.org/wiki/F-algebra.
Groups are among the things studied in the field of algebra. Groups aren't algebras in the second, specific, sense. They are F-algebras. Most mathematicians, most of the time, would not call groups "algebras" without some qualifier like that F- prefix.
The term "Clifford algebra" also means some different things.
A Clifford algebra is a particular sort of algebra-in-the-second-sense. The field called Clifford algebra is the study of those things. These days people more often say "geometric algebra" rather than "Clifford algebra" for that meaning.
There are mathematical objects called Clifford groups. They are not at all the same thing as Clifford algebras, and you can study Clifford algebras in some depth without paying any attention to the Clifford groups. But they are closely related to the Clifford algebras.
Both Clifford groups and Clifford algebras have applications in quantum physics and, more specifically, in quantum computing. But so far as I know the ways in which you use them in quantum computing has very little to do with the ways in which you use Clifford algebras for doing geometry. It is quite common in mathematics for the same (or equivalent) objects and structures to turn up in multiple places, in unrelated-looking ways. Sometimes this gives rise to deep connections between different fields; sometimes it's just a coincidence. I don't know enough about either quantum computation or geometric algebra to know which of those is going on here, but my intuition leans toward "coincidence".
So. vtomole's original comment was kinda-right and kinda-wrong: yes, there is a connection between Clifford algebras and quantum computation, but it doesn't have much to do with the stuff discussed, e.g., at the far end of the top-level link here. knzhou's question was a good one, pointing out that the two topics are quite separate. vtomole's reply "A group is an algebraic structure ..." didn't make any untrue statements but did miss the point; the fact that a group is an algebraic structure doesn't mean that something called "the X group" necessarily has anything to do with something called "the X algebra" -- though it happens that in this case there is a connection. (vtomole clearly got the point soon after, as seen from their subsequent replies.) knzhou was correct to point out that vtomole's reply missed the point. lisper, again, didn't say anything untrue but I think he missed the point. klodolph's comment about algebras versus universal algebras versus algebra was spot-on and the only reason why I went into more detail above is that it was apparently too brief to be clearly understood. monoideism is right that (e.g.) a group is a universal algebra, wrong to say that klodolph is self-contradictory, and I think missing the point that "algebra" is used with different meanings on different occasions, and in the phrase "Clifford algebra" the specific meaning in question is not "universal algebra". (Even though a Clifford algebra is, also, an example of a universal algebra.)
The fact that a group is a universal algebra doesn't at all licence any sort of blurring of the distinction between Clifford groups and Clifford algebras. The meaning of "algebra" in "Clifford algebra" is not "universal algebra" or "F-algebra", it is "vector space with multiplication", and a group simply isn't one of those (well, some groups are, but e.g. the Clifford groups are not).